Searcharxiv⌕ Search

arXiv · 0709.2202

Linear maps preserving fibers

Abstract

Let $G\subset\GL(V)$ be a complex reductive group where $\dim V<\infty$, and let $π\colon V\to\quot VG$ be the categorical quotient. Let $\NN:=π\invπ(0)$ be the null cone of $V$, let $H_0$ be the subgroup of $\GL(V)$ which preserves the ideal $\I$ of $\NN$ and let $H$ be a Levi subgroup of $H_0$ containing $G$. We determine the identity component of $H$. In many cases we show that $H=H_0$. For adjoint representations we have $H=H_0$ and we determine $H$ completely. We also investigate the subgroup $G_F$ of $\GL(V)$ preserving a fiber $F$ of $π$ when $V$ is an irreducible cofree $G$-module.

Explore related subjects

Keep this discovery

Explore connections, maps & timelines

BibTeXRIS

Gerald W. Schwarz. 2008-01-18. Linear maps preserving fibers. https://arxiv.org/abs/0709.2202

Cite the original work for its findings. Save a collection to share your selection of sources.

KEEP EXPLORING

Related papers

Left and right zero subsemigroups and an elementary approach to the Rees-Sushkevich Theorem

In a semigroup $S$ with idempotent $e$, the set of all elements $a$ of $S$ such that $ae=a$ and $ea=e$ forms the maximum left zero subsemigroup of $S$ containing $e$, and the set of all elements $b$ of $S$ such that $be=e$ and $eb=b$ forms the maximum right zero subsemigroup of $S$ containing $e$. We use these maximal right and left zero subsemigroups along with the maximal subgroups of a semigroup in the determination of maximal right and left subgroups, rectangular band subsemigroups, completely simple subsemigroups, rectangular subgroups, and completely $0$-simple subsemigroups. An elementary approach of the Rees-Sushkevich Theorem follows. Then we define rectangular $0$-bands and rectangular $0$-groups as completely $0$-simple analogues of rectangular bands and rectangular groups.

math.GR↗

Common overlattices in trees and trees with fins

Bass and Kulkarni proved that any pair of free uniform lattices in the automorphism group of a tree have conjugates that both lie inside a third uniform lattice (which is not necessarily free). We show that this does not generalise to trees with fins. The construction of our counter-example involves working with a certain generalisation of the universal groups of Burger and Mozes.

math.GR↗