arXiv · 1303.0815
Products of sequentially compact spaces and compactness with respect to a set of filters
Abstract
We show that, under suitably general formulations, covering properties, accumulation properties and filter convergence are all equivalent notions. This general correspondence is exemplified in the study of products. Let $X$ be a product of topological spaces. We prove that $X$ is sequentially compact if and only if all subproducts by $\leq \mathfrak s$ factors are sequentially compact. If $\mathfrak s = \mathfrak h$, then $X$ is sequentially compact if and only if all factors are sequentially compact and all but at most $<\mathfrak s$ factors are ultraconnected. We give a topological proof of the inequality ${\rm cf} \mathfrak s \geq \mathfrak h$. Recall that $\mathfrak s$ denotes the splitting number and $\mathfrak h$ the distributivity number. The product $X$ is Lindel\"of if and only if all subproducts by $\leq \omega_1 $ factors are Lindel\"of. Parallel results are obtained for final $ \omega_n$-compactness, $[ \lambda, \mu ]$-compactness, the Menger and Rothberger properties.
Explore related subjects
Keep this discovery
Paolo Lipparini. 2013-03-04. Products of sequentially compact spaces and compactness with respect to a set of filters. https://doi.org/10.13137/2464-8728/34003
Cite the original work for its findings. Save a collection to share your selection of sources.