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arXiv · 1603.00454

There are no intermediate structures between the group of integers and Presburger arithmetic

Gabriel Conant
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Abstract

We show that if a first-order structure $\mathcal{M}$, with universe $\mathbb{Z}$, is an expansion of $(\mathbb{Z},+,0)$ and a reduct of $(\mathbb{Z},+,<,0)$, then $\mathcal{M}$ must be interdefinable with $(\mathbb{Z},+,0)$ or $(\mathbb{Z},+,<,0)$.

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Gabriel Conant. 2016-03-01. There are no intermediate structures between the group of integers and Presburger arithmetic. https://arxiv.org/abs/1603.00454

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