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arXiv · 1801.09640

True value of an integral in Gradshteyn and Ryzhik's table

J. Arias de Reyna
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Abstract

Victor Moll pointed out that entry 3.248.5 in the sixth edition of Gradshteyn and Ryzhik tables of integrals was incorrect. He asked some years ago what was the true value of this integral. I evaluate it in terms of two elliptic integrals. The evaluation is standard but involved, using real and complex analysis. I prove $$\int_0^{\infty}\frac{dx}{(1+x^2)^{3/2}[\varphi(x)+\sqrt{\varphi(x)}]^{1/2}}= \frac{\sqrt{3}-1}{\sqrt{2}}\Pi(\pi/2,k,3^{-1/2})-\frac{1}{\sqrt{2}}F(\alpha, 3^{-1/2}),$$ where $\varphi(x)=1+4x^2/2(1+x^2)^2$, $k=2-\sqrt{3}$, $\alpha=\arcsin\sqrt{k}$ and $F(\varphi,k)$, $\Pi(\varphi,n^2,k)$ the elliptic integrals of the first and third kind respectively.

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J. Arias de Reyna. 2018-01-29. True value of an integral in Gradshteyn and Ryzhik's table. https://arxiv.org/abs/1801.09640

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