Aut($\Gamma$)=det($M_\Gamma$)

Zhonggan Huang

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arXiv · 1807.01580

Aut($\Gamma$)=det($M_\Gamma$)

Zhonggan Huang

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Abstract

In this article, we will show that the automorphism group of any hypergraph is essentially equal to the determinant of some matrix over a ring generated from the set of ground points. With this, we are also able to determine whether two graphs are isomorphic.

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Zhonggan Huang. 2018-07-03. Aut($\Gamma$)=det($M_\Gamma$). https://arxiv.org/abs/1807.01580

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