Asymptotically Optimal Circuit Depth for Quantum State Preparation and General Unitary Synthesis

Abstract

The Quantum State Preparation problem aims to prepare an $n$-qubit quantum state $|\psi_v\rangle =\sum_{k=0}^{2^n-1}v_k|k\rangle$ from the initial state $|0\rangle^{\otimes n}$, for a given unit vector $v=(v_0,v_1,v_2,\ldots,v_{2^n-1})^T\in \mathbb{C}^{2^n}$ with $\|v\|_2 = 1$. The problem is of fundamental importance in quantum algorithm design, Hamiltonian simulation and quantum machine learning, yet its circuit depth and size complexity remain open when ancillary qubits are available. In this paper, we study efficient constructions of quantum circuits with $m$ ancillary qubits that can prepare $|\psi_v\rangle$ in depth $\tilde O\left(\frac{2^n}{m+n}+n\right)$and size $O(2^n)$, achieving the optimal value for both measures simultaneously. These results also imply a depth complexity of $\Theta(4^n/(m+n))$ for quantum circuits implementing a general $n$-qubit unitary using $m = O(2^n/n)$ ancillary qubits. This resolves the depth complexity for circuits without ancillary qubits, and for circuits with exponentially many ancillary qubits, this gives a quadratic saving from $O(4^n)$ to $\tilde \Theta(2^n)$. Our circuits are deterministic, prepare the state and carry out the unitary precisely, utilize the ancillary qubits tightly and the depths are optimal in a wide range of parameter regime. The results can be viewed as (optimal) time-space tradeoff bounds, which is not only theoretically interesting, but also practically relevant in the current trend that the number of qubits starts to take off, by showing a way to use a large number of qubits to compensate the short qubit lifetime.