arXiv · 2208.08414
Another proof of Cruse's theorem and a new necessary condition for completion of partial Latin squares (Part 3.)
Abstract
A partial Latin square of order n can be represented by a 3-dimensional chess-board of size n x n x n with at most n^2 non-attacking rooks. Based on this representation, we give proofs of the theorems of M. Hall, Ryser and Cruse on the completion of partial Latin squares that share a common device, the cover sheet: in each case the cover sheet is extended to a (0,1)-matrix with constant line sums and decomposed into permutation matrices by Konig's theorem. With the help of this proof, we extend the scope of Cruse's theorem to compact bricks, which appear to be independent of their environment. Without losing any completion you can replace a dot by a rook if the dot must become a rook, or you can eliminate the dots that are known not to become rooks. Therefore, we introduce primary and secondary extension procedures that are repeated as many times as possible. If the procedures do not decide whether a PLSC can be completed or not, a new necessary condition for completion can be formulated for the dot structure of the resulting PLSC, the BUG condition.
Explore related subjects
Keep this discovery
Béla Jónás. 2022-08-17. Another proof of Cruse's theorem and a new necessary condition for completion of partial Latin squares (Part 3.). https://arxiv.org/abs/2208.08414
Cite the original work for its findings. Save a collection to share your selection of sources.