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arXiv · 2407.07079

Taut visibility domains are not necessarily Kobayashi complete

Rumpa Masanta
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Abstract

We answer a question asked recently by Banik in the negative by showing that for each $n\geq 2$, there exists a taut visibility domain in $\mathbb{C}^n$ that is not Kobayashi complete. The domains that we produce are bounded and have boundaries that are very regular away from a single point.

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Rumpa Masanta. 2024-07-09. Taut visibility domains are not necessarily Kobayashi complete. https://arxiv.org/abs/2407.07079

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