arXiv · 2605.09293
On two conjectures of Ho\`ang
Abstract
A graph $G$ is said to be perfectly divisible if for every induced subgraph $H$ of $G$ with at least one edge, the vertex set $V(H)$ can be partitioned into two sets $A, B$ such that $H[A]$ is perfect and $\omega(B) < \omega(H)$. It is easy to see that the chromatic number of a perfectly divisible graph is at most $\binom{\omega(G)+1}{2}$. Ho\`ang conjectured that every graph $G$ with $\alpha(G) \le 3$ is perfectly divisible. We disprove this conjecture. In the same vein, a graph $G$ with at least one edge is $k$-divisible if for every induced subgraph $H$ of $G$ with at least one edge, the vertex set $V(H)$ can be partitioned into $k$ sets, none of which contains a largest clique of $H$. It is easy to see that the chromatic number of a $k$-divisible graph is at most $k^{\omega-1}$. Ho\`ang conjectured that every even-hole-free graph is 3-divisible. We confirm this conjecture.
Explore related subjects
Keep this discovery
Hongzhang Chen, Kaiyang Lan, Wenlong Zhong. 2026-05-10. On two conjectures of Ho\`ang. https://arxiv.org/abs/2605.09293
Cite the original work for its findings. Save a collection to share your selection of sources.