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Is the a_0(1450) a candidate for the lowest q\bar{q} ^3P_0 state?

A. M. Badalian
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Abstract

For the $a_0(1450)$, considered as the $q\bar{q} 1^3P_0$ state, "experimental" tensor splitting, $c_{exp}=(-150\pm 40$) MeV, appears to be in contradiction with conventional theory of fine structure. There is no such discrepancy if the $a_0(980)$ belongs to the $1^3P_J q\bar{q}$ multiplet. The hadronic shift of the $a_0(980)$ is shown to be strongly dependent on the value of the strong coupling in spin-dependent interaction.

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A. M. Badalian. 2003-06-30. Is the a_0(1450) a candidate for the lowest q\bar{q} ^3P_0 state?. https://doi.org/10.1134/1.1592589

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