The scalar radius of the pion

Abstract

The pion scalar radius is given by $ =(6/π)\int_{4M^2_π}^\infty{\rm d}s δ_S(s)/s^2$, with $δ_S$ the phase of the scalar form factor. Below $\bar{K}K$ threshold, $δ_S=δ_π$, $δ_π$ being the isoscalar, S-wave $ππ$ phase shift. At high energy, $s>2 {\rm GeV}^2$, $δ_S$ is given by perturbative QCD. In between I argued, in a previous letter, that one can interpolate $δ_S\simδ_π$, because inelasticity is small, compared with the errors. This gives $ =0.75\pm0.07 {\rm fm}^2$. Recently, Ananthanarayan, Caprini, Colangelo, Gasser and Leutwyler (ACCGL) have claimed that this is incorrect and one should have instead $δ_S\simeqδ_π-π$; then $ =0.61\pm0.04 {\rm fm}^2$. Here I show that the ACCGL phase $δ_S$ is pathological in that it is discontinuous for small inelasticity, does not coincide with what perturbative QCD suggests at high energy, and only occurs because these authors take a value for $δ_π(4m^2_K)$ different from what experiment indicates. If one uses the value for $δ_π(4m^2_K)$ favoured by experiment, the ensuing phase $δ_S$ is continuous, agrees with perturbative QCD expectations, and satisfies $δ_S\simeqδ_π$, thus confirming the correctness of my previous estimate, $ =0.75\pm0.07 {\rm fm}^2$.