arXiv · math/0511370
When is a non-self-adjoint Hill operator a spectral operator of scalar type?
Abstract
We derive necessary and sufficient conditions for a one-dimensional periodic Schrödinger (i.e., Hill) operator H=-d^2/dx^2+V in L^2(R) to be a spectral operator of scalar type. The conditions demonstrate the remarkable fact that the property of a Hill operator being a spectral operator is independent of smoothness (or even analyticity) properties of the potential V.
Explore related subjects
Keep this discovery
Fritz Gesztesy, Vadim Tkachenko. 2005-11-15. When is a non-self-adjoint Hill operator a spectral operator of scalar type?. https://arxiv.org/abs/math/0511370
Cite the original work for its findings. Save a collection to share your selection of sources.