arXiv · math/9308212
On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2
Abstract
We prove the consistency of ``CH + 2^{aleph_1} is arbitrarily large + 2^{aleph_1} not-> (omega_1 x omega)^2_2''. If fact, we can get 2^{aleph_1} not-> [omega_1 x omega]^2_{aleph_0}. In addition to this theorem, we give generalizations to other cardinals.
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Saharon Shelah. 1993-08-15. On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2. https://arxiv.org/abs/math/9308212
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