Induced long range dipole field enhanced antihydrogen formation in the $\bar{p}+ Ps(n=2)\to e^- + \bar{H}(n\le 2)$ reaction
We assume all interaction to be Coulombic and solve the modified Faddeev equation for energies between the $Ps(n=2)$ and $\bar{H}(n=3)$, which involve six and eight open channels. We find that 99% of the antihydrogen are formed in $\bar{H}(n=2)$. Just above the $Ps(n=2)$ threshold the S, P, and D partial waves contribute more than 4000 square Bohr radii near the maximum. Evidences indicate that the induced long range dipole potential from the degenerate $Ps(n=2)$ targets is responsible for such a large antihydrogen formation cross section.
physics.atom-ph↗