Diophantine approximation and the equation (a^2 c x^k - 1)(b^2 c y^k - 1) = (abc z^k - 1)^2
We prove that the Diophantine equation (a^2 c x^k - 1)(b^2 c y^k - 1) = (abc z^k - 1)^2 has no solutions in positive integers with x, y, z > 1, k \geq 7 and a^2x^k \neq b^2y^k.
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