Searcharxiv⌕ Search

arXiv subjects

Huihui Zhu

Publications and source records attributed to Huihui Zhu.

25 records · Page 2Linked to original sources

The inverse along a product and its applications

In this paper, we study the recently defined notion of the inverse along an element. An existence criterion for the inverse along a product is given in a ring. As applications, we present the equivalent conditions for the existence and expressions of the inverse along a matrix.

math.RA↗

Additive and product properties of Drazin inverses of elements in a ring

We study the Drazin inverses of the sum and product of two elements in a ring. For Drazin invertible elements $a$ and $b$ such that $a^2b=aba$ and $b^2a=bab$, it is shown that $ab$ is Drazin invertible and that $a+b$ is Drazin invertible if and only if $1+a^Db$ is Drazin invertible. Moreover, the formulae of $(ab)^D$ and $(a+b)^D$ are presented. Thus, a generalization of the main result of Zhuang, Chen et al. (Linear Multilinear Algebra 60 (2012) 903-910) is given.

math.RA↗

Additive property of pseudo Drazin inverse of elements in a Banach algebra

We study properties of pseudo Drazin inverse in a Banach algebra with unity 1. If $ab=ba$ and $a,b$ are pseudo Drazin invertible, we prove that $a+b$ is pseudo Drazin invertible if and only if $1+a^‡b$ is pseudo Drazin invertible. Moreover, the formula of $(a+b)^‡$ is presented . When the commutative condition is weaken to $ab=λba ~(λ\neq 0)$, we also show that $a-b$ is pseudo Drazin invertible if and only if $aa^‡(a-b)bb^‡$ is pseudo Drazin invertible.

math.RA↗

Additive Property of Drazin Invertibility of Elements

In this article, we investigate additive properties of the Drazin inverse of elements in rings and algebras over an arbitrary field. Under the weakly commutative condition of $ab = λba$, we show that $a-b$ is Drazin invertible if and only if $aa^{D}(a-b)bb^{D}$ is Drazin invertible. Next, we give explicit representations of $(a+b)^{D}$, as a function of $a, b, a^{D}$ and $b^{D}$, under the conditions $a^{3}b = ba$ and $b^{3}a = ab$.

math.RA↗