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Ji-won Park

Publications and source records attributed to Ji-won Park.

4 recordsLinked to original sources

Packing d-dimensional balls into a d+1-dimensional container

In this article, we consider the problems of finding in $d+1$ dimensions a minimum-volume axis-parallel box, a minimum-volume arbitrarily-oriented box and a minimum-volume convex body into which a given set of $d$-dimensional unit-radius balls can be packed under translations. The computational problem is neither known to be NP-hard nor to be in NP. We give a constant-factor approximation algorithm for each of these containers based on a reduction to finding a shortest Hamiltonian path in a weighted graph, which in turn models the problem of stabbing the centers of the input balls while keeping them disjoint. We also show that for $n$ such balls, a container of volume $O(n^{\frac{d-1}{d}})$ is always sufficient and sometimes necessary. As a byproduct, this implies that for $d \geq 2$ there is no finite size $(d+1)$-dimensional convex body into which all $d$-dimensional unit-radius balls can be packed simultaneously.

cs.CG

Bundled Crossings Revisited

An effective way to reduce clutter in a graph drawing that has (many) crossings is to group edges that travel in parallel into \emph{bundles}. Each edge can participate in many such bundles. Any crossing in this bundled graph occurs between two bundles, i.e., as a \emph{bundled crossing}. We consider the problem of bundled crossing minimization: A graph is given and the goal is to find a bundled drawing with at most $k$ bundled crossings. We show that the problem is NP-hard when we require a simple drawing. Our main result is an FPT algorithm (in $k$) when we require a simple circular layout. These results make use of the connection between bundled crossings and graph genus.

cs.CG

Faster Algorithms for Growing Prioritized Disks and Rectangles

Motivated by map labeling, Funke, Krumpe, and Storandt [IWOCA 2016] introduced the following problem: we are given a sequence of $n$ disks in the plane. Initially, all disks have radius $0$, and they grow at constant, but possibly different, speeds. Whenever two disks touch, the one with the higher index disappears. The goal is to determine the elimination order, i.e., the order in which the disks disappear. We provide the first general subquadratic algorithm for this problem. Our solution extends to other shapes (e.g., rectangles), and it works in any fixed dimension. We also describe an alternative algorithm that is based on quadtrees. Its running time is $O\big(n \big(\log n + \min \{ \log Δ, \log Φ\}\big)\big)$, where $Δ$ is the ratio of the fastest and the slowest growth rate and $Φ$ is the ratio of the largest and the smallest distance between two disk centers. This improves the running times of previous algorithms by Funke, Krumpe, and Storandt [IWOCA 2016], Bahrdt et al. [ALENEX 2017], and Funke and Storandt [EuroCG 2017]. Finally, we give an $Ω(n\log n)$ lower bound, showing that our quadtree algorithms are almost tight.

cs.CG

Obstructing Visibilities with One Obstacle

Obstacle representations of graphs have been investigated quite intensely over the last few years. We focus on graphs that can be represented by a single obstacle. Given a (topologically open) polygon $C$ and a finite set $P$ of points in general position in the complement of $C$, the visibility graph $G_C(P)$ has a vertex for each point in $P$ and an edge $pq$ for any two points $p$ and $q$ in $P$ that can see each other, that is, $\overline{pq} \cap C=\emptyset$. We draw $G_C(P)$ straight-line. Given a graph $G$, we want to compute an obstacle representation of $G$, that is, an obstacle $C$ and a set of points $P$ such that $G=G_C(P)$. The complexity of this problem is open, even for the case that the points are exactly the vertices of a simple polygon and the obstacle is the complement of the polygon-the simple-polygon visibility graph problem. There are two types of obstacles; an inside obstacle lies in a bounded component of the complement of the visibility drawing, whereas an outside obstacle lies in the unbounded component. We show that the class of graphs with an inside-obstacle representation is incomparable with the class of graphs that have an outside-obstacle representation. We further show that any graph with at most seven vertices or circumference at most 6 has an outside-obstacle representation, which does not hold for a specific graph with 8 vertices and circumference 8. Finally, we consider the outside-obstacle graph sandwich problem: given graphs $G$ and $H$ on the same vertex set, is there a graph $K$ such that $G \subseteq K \subseteq H$ and $K$ has an outside-obstacle representation? We show that this problem is NP-hard even for co-bipartite graphs. With slight modifications, our proof also shows that the inside-obstacle graph sandwich problem, the single-obstacle graph sandwich problem, and the simple-polygon visibility graph sandwich problem are all NP-hard.

cs.CG