SearcharxivSearch

arXiv subjects

K. M. Hui

Publications and source records attributed to K. M. Hui.

2 recordsLinked to original sources

Existence of hypercylinder expanders of the inverse mean curvature flow

We will give a new proof of the existence of hypercylinder expander of the inverse mean curvature flow which is a radially symmetric homothetic soliton of the inverse mean curvature flow in $\mathbb{R}^n\times \mathbb{R}$, $n\ge 2$, of the form $(r,y(r))$ or $(r(y),y)$ where $r=|x|$, $x\in\mathbb{R}^n$, is the radially symmetric coordinate and $y\in \mathbb{R}$. More precisely for any $λ>\frac{1}{n-1}$ and $μ>0$, we will give a new proof of the existence of a unique even solution $r(y)$ of the equation $\frac{r''(y)}{1+r'(y)^2}=\frac{n-1}{r(y)}-\frac{1+r'(y)^2}{λ(r(y)-yr'(y))}$ in $\mathbb{R}$ which satisfies $r(0)=μ$, $r'(0)=0$ and $r(y)>yr'(y)>0$ for any $y\in\mathbb{R}$. We will prove that $\lim_{y\to\infty}r(y)=\infty$ and $a_1:=\lim_{y\to\infty}r'(y)$ exists with $0\le a_1<\infty$. We will also give a new proof of the existence of a constant $y_1>0$ such that $r''(y_1)=0$, $r''(y)>0$ for any $0 y_1$.

math.AP

Existence of self-similar solution of the inverse mean curvature flow

We will give a new proof of a recent result of P.~Daskalopoulos, G.Huisken and J.R.King ([DH] and reference [7] of [DH]) on the existence of self-similar solution of the inverse mean curvature flow which is the graph of a radially symmetric solution in $\mathbb{R}^n$, $n\ge 2$, of the form $u(x,t)=e^{λt}f(e^{-λt} x)$ for any constants $λ>\frac{1}{n-1}$ and $μ<0$ such that $f(0)=μ$. More precisely we will give a new proof of the existence of a unique radially symmetric solution $f$ of the equation $\mbox{div}\,\left(\frac{\nabla f}{\sqrt{1+|\nabla f|^2}} \right)=\frac{1}λ\cdot\frac{\sqrt{1+|\nabla f|^2}}{x\cdot\nabla f-f}$ in $\mathbb{R}^n$, $f(0)=μ$, for any $λ>\frac{1}{n-1}$ and $μ<0$, which satisfies $f_r(r)>0$, $f_{rr}(r)>0$ and $rf_r(r)>f(r)$ for all $r>0$. We will also prove that $\lim_{r\to\infty}\frac{rf_r(r)}{f(r)}=\frac{λ(n-1)}{λ(n-1)-1}$.

math.AP