arXiv2021
The Kurth solution is a particular non-isotropic steady state solution to the gravitational Vlasov-Poisson system. It has the property that by means of a suitable time-dependent transformation it can be turned into a family of time-dependent solutions. Therefore, for a general steady state $Q(x, v)=\tilde{Q}(e_Q, β)$, depending upon the particle energy $e_Q$ and $β=\ell^2=|x\wedge v|^2$, the question arises if solutions $f$ could be generated that are of the form \[ f(t)=\tilde{Q}\Big(e_Q(R(t), P(t), B(t)), B(t)\Big) \] for suitable functions $R$, $P$ and $B$, all depending on $(t, r, p_r, β)$ for $r=|x|$ and $p_r=\frac{x\cdot v}{|x|}$. We are going to show that, under some mild assumptions, basically if $R$ and $P$ are independent of $β$, and if $B=β$ is constant, then $Q$ already has to be the Kurth solution. This paper is dedicated to the memory of Professor Robert Glassey.