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arXiv · 2004.14310

Normal functionals on Lipschitz spaces are weak$^\ast$ continuous

Ramón J. Aliaga·Eva Pernecká
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Abstract

Let $\operatorname{Lip}_0(M)$ be the space of Lipschitz functions on a complete metric space $M$ that vanish at a base point. We show that every normal functional in $\operatorname{Lip}_0(M)^\ast$ is weak$^*$ continuous, answering a question by N. Weaver.

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BibTeXRIS

Ramón J. Aliaga, Eva Pernecká. 2020-04-29. Normal functionals on Lipschitz spaces are weak$^\ast$ continuous. https://doi.org/10.1017/s147474802100013x

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