arXiv · 2404.04348
On existence of hyperinvariant subspaces for quasinilpotent operators with a nonsymmetry in the growth of the resolvent
Abstract
Let $T$ be a quasinilpotent operator on a Banach space. Under assumptions of a certain nonsymmetry in the growth of the resolvent of $T$, it is proved that every operator in the commutant of $T$ is not unicellular. In particular, $T$ has nontrivial hyperinvariant subspaces. The proof is based on a modification of the reasoning of [S].
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Maria F. Gamal'. 2024-04-05. On existence of hyperinvariant subspaces for quasinilpotent operators with a nonsymmetry in the growth of the resolvent. https://arxiv.org/abs/2404.04348
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