Measurements of the branching fractions of $\Xi_{c}^{+}\to \Sigma^{+}K_{S}^{0}$, $\Xi_{c}^{+}\to \Xi^{0}\pi^{+}$, and $\Xi_{c}^{+}\to \Xi^{0}K^{+}$ at Belle and Belle II

Abstract

Using 983.0 $\rm{fb}^{-1}$ and 427.9 $\rm{fb}^{-1}$ data samples collected with the Belle and Belle II detectors at the KEKB and SuperKEKB asymmetric energy $e^+e^-$ colliders, respectively, we present studies of the Cabibbo-favored $\Xi_c^+$ decays ${\Xi_{c}^{+}\to \Sigma^{+}K_{S}^{0}}$ and $\Xi_{c}^{+}\to \Xi^{0}\pi^{+}$, and the singly Cabibbo-suppressed decay $\Xi_{c}^{+}\to \Xi^{0}K^{+}$. The ratios of branching fractions of ${\Xi_{c}^{+}\to \Sigma^{+}K_{S}^{0}}$ and $\Xi_{c}^{+}\to \Xi^{0}K^{+}$ relative to that of $\Xi_{c}^{+}\to\Xi^{-}\pi^{+}\pi^{+}$ are measured for the first time, while the ratio ${\cal B}(\Xi_{c}^{+}\to\Xi^{0}\pi^{+})/{\cal B}(\Xi_{c}^{+}\to\Xi^{-}\pi^{+}\pi^{+}) $ is also determined and improved by an order of magnitude in precision. The measured branching fraction ratios are $\frac{\cal{B}(\Xi_{c}^{+} \to \Sigma^{+}K_{S}^{0})}{\cal{B}(\Xi_{c}^{+}\to \Xi^{-}\pi^{+}\pi^+)}= 0.067 \pm 0.007 \pm 0.003$, $\frac{\cal{B}(\Xi_c^{+} \to \Xi^{0}\pi^{+})}{\cal{B}(\Xi_{c}^{+}\to \Xi^{-}\pi^{+}\pi^+)} = 0.251 \pm 0.005 \pm 0.010$, $\frac{\cal{B}(\Xi_c^{+} \to \Xi^{0}K^{+})}{\cal{B}(\Xi_{c}^{+}\to \Xi^{-}\pi^{+}\pi^+)} = 0.017 \pm 0.003 \pm 0.001$. Additionally, the ratio ${\cal B}(\Xi_{c}^{+}\to\Xi^{0}K^{+})/{\cal B}(\Xi_{c}^{+}\to\Xi^{0}\pi^{+})$ is measured to be $ 0.068 \pm 0.010 \pm 0.004$. Here, the first and second uncertainties are statistical and systematic, respectively. Multiplying the ratios by the branching fraction of the normalization mode, ${\mathcal B}(\Xi_{c}^{+}\to\Xi^{-}\pi^{+}\pi^+)= (2.9\pm 1.3)\%$, we obtain the following absolute branching fractions ${\cal B}(\Xi_{c}^{+}\to\Sigma^{+}K^{0}_{S}) = (0.194 \pm 0.021 \pm 0.009 \pm 0.087 )%$, ${\cal B}(\Xi_{c}^{+}\to\Xi^{0}\pi^{+}) = (0.728 \pm 0.014 \pm 0.027 \pm 0.326 )%$, ${\cal B}(\Xi_{c}^{+}\to\Xi^{0}K^{+}) = (0.049 \pm 0.007 \pm 0.003 \pm 0.022 )%$.